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Parse date(today) into a fixed - user local independent - format?
Dear All,
1) How can you ensure that the output of function today() is independent from the user local? I get different formats of the same date depending the date format settings of the user.
2) I am looking to use this format: DDMMYY; thus for instance 240919.
Thanks,
Bas
1 reply
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Try
format(today(), "DDMMYY")
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