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openURL(string) Error
When I use openURL(string) on a buttion, it returns this error.
Is there any way for it to automatically use safari as the defult browser rather than constantly choosing the application to open, I have to do this every time and it wont register it as safari :( .
1 reply
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Make sure to prefix your string starts with http:// or https:// ... I was able to repeat this error by dropping the prefix.
So openURL("https://www.google.com")
works.
Content aside
- 6 yrs agoLast active
- 1Replies
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