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Filter an array based on a Multichoice using another Multichoice

arrayInarray.ninox

So I was wondering how to filter an array that will keep NId and then compare a basic multichoice with another basic multichoice.

If you open the attached DB, in Table1 on the first tab you will see what I'm trying to do.

I have a multichoice (with four choices) that match the multichoice in Table2. I have 6 records linked to the one record in Table1. I want to now filter a view element so whatever I select in the multichoice it will filter out records that don't match the selections.

I thought I could do:

let c := Table2;
let lm := numbers(pMultichoice);
c[var v := numbers(cMultichoice);
    count(v[(var subv := this;
                count(lm[= subv] > 0)) > 0])]

but it always returns all records.

Thanks,

3 replies

null
    • Ninox developper
    • Jacques_TUR
    • 2 yrs ago
    • Reported - view

    It's just a bad position of the brackets:

    In your code, the first ">0" is placed after "lm[= subv] " and not after the count function:

    c[
    var v := numbers(cMultichoice);
    count(
        v[
        (var subv := this;
        count(lm[= subv] > 0)
        ) > 0]
        )
    ]

    The code is correct when each ">0" is placed at the end of the count function:

    c[
    var v := numbers(cMultichoice);
    count(
        v[
            var subv := this;
            count(lm[= subv]) > 0
        ]) > 0
 ]
    • Fred
    • 2 yrs ago
    • Reported - view

    Thanks, Jacques. It is nice to know I was on the right track. I wasn't sure if I could do the count in another count.

    • Fred
    • 2 yrs ago
    • Reported - view

    Looking back at the post that start all of this I realized that Jacques had already answered this question.

    var a := numbers('Select characteristics');
select Contact
    where (var b := numbers('list of characteristics');
    count(a[var v := this;
                count(b[= v]) > 0]) > 0)

    I think at the time I couldn't process what was written. I don't know how many times I've re-read the post trying to make sure I understand what is going on.

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  • Status Answered
  • 2 yrs agoLast active
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