agiorno, Here are a couple of options...

Option 1

let dateArray := [today()];
for i from 1 to 3 do
dateArray := unique(dateArray, today() + i)
end;
format(item(dateArray, 0), "DD/MM/YYYY") + ", " + format(item(dateArray, 1), "DD/MM/YYYY") + ", " + format(item(dateArray, 2), "DD/MM/YYYY")

Option 2

let numToday := number(today());
let oneDay := 86400000;
let numDates := range(numToday, numToday + oneDay * 3, oneDay);
format(date(item(numDates, 0)), "DD/MM/YYYY") + ", " + format(date(item(numDates, 1)), "DD/MM/YYYY") + ", " + format(date(item(numDates, 2)), "DD/MM/YYYY")

If you paste the code in two separate Formula fields you will see the output is the same.

Agiorno, you're welcome. The unique() function allows you to combine arrays and add items to arrays as long as they are unique. The function will remove duplicate items. In the line you are asking about the function is adding the iterative value of "i" (1 & 2 because the "To" value is not inclusive) to today(). It is equivalent to today() + 1 and today() + 2. Hope this helps!

Agiorno, Do you have a pattern or rule you are using to exclude dates?

Agiorno, something like the following is the only thing I can work out...

let dateArray := [today()];
for i from 1 to 5 do
dateArray := unique(dateArray, today() + i)
end;
let firstArray := [item(dateArray, 1), item(dateArray, 3), item(dateArray, 1)];
let secondArray := [item(dateArray, 0), item(dateArray, 2)];
concat(firstArray);
concat(secondArray)

Is it between "two dates" or "two date arrays"?

Here is between two dates.